document.write( "Question 115426: Please help.\r
\n" ); document.write( "\n" ); document.write( "Solve the following system by substitution\r
\n" ); document.write( "\n" ); document.write( "x + y = 12
\n" ); document.write( " y = 2x\r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "JMS
\n" ); document.write( "

Algebra.Com's Answer #83998 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
Y=2X NOW REPLACE Y WITH (2X & SOLVE FOR Y IN THE OTHER EQUATION.X+2X=12
\n" ); document.write( "3X=12
\n" ); document.write( "X=12/3
\n" ); document.write( "X=4 ANSWER.
\n" ); document.write( "Y=2*4
\n" ); document.write( "Y=8 ANSWER.
\n" ); document.write( "PROOF
\n" ); document.write( "4+8=12
\n" ); document.write( "12=12
\n" ); document.write( "
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