document.write( "Question 1203978: Three assembly lines are used to produce a certain component for an airliner. To examine the production rate, a random sample of six hourly periods is chosen for each assembly line and the number of components produced during these periods for each line is recorded. The output from a statistical software package is:\r
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\n" ); document.write( "\n" ); document.write( "Summary
\n" ); document.write( "Groups Sample Size Sum Average Variance
\n" ); document.write( "Line A 6 250 41.66667 0.266667
\n" ); document.write( "Line B 6 260 43.33333 0.666667
\n" ); document.write( "Line C 6 249 41.5 0.7
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\n" ); document.write( "\n" ); document.write( "ANOVA
\n" ); document.write( "Source of Variation SS df MS F p-value
\n" ); document.write( "Between Groups 12.33333 2 6.166667 11.32653 0.001005
\n" ); document.write( "Within Groups 8.166667 15 0.544444
\n" ); document.write( "Total 20.5 17 \r
\n" ); document.write( "\n" ); document.write( "Compute 99% confidence intervals that estimate the difference between each pair of means. (Negative amount should be indicated by a minus sign. Round your answers to 2 decimal places.) Which pairs of means are statistically different?
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Algebra.Com's Answer #839960 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
i found a calculator online at https://statpages.info/anova1sm.htmlthat does the analysis you are looking for.
\n" ); document.write( "it works off the mean and the standard deviation, i.e. uses summarized data.
\n" ); document.write( "i used the summarized data you had and got similar results.
\n" ); document.write( "this indicates to me that the results were consistent with what you got.
\n" ); document.write( "it also does the sample to sample posthoc analysis.
\n" ); document.write( "the results as shown below.\r
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\n" ); document.write( "\n" ); document.write( "group 1 was line A
\n" ); document.write( "group 2 was line B
\n" ); document.write( "group 3 was line C.\r
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\n" ); document.write( "\n" ); document.write( "the results indicate that line A to line B are statistically different from each other because the p-value was .0037 which is less than .01.\r
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\n" ); document.write( "\n" ); document.write( "standard deviation = square root of variance, so i took the square root of the variance given and used that as input to the calculator.
\n" ); document.write( "i round to 6 decimal digits which is usually enough for accurate readings.\r
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