document.write( "Question 1203986: Charles made a business trip of 200.5
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document.write( " miles. He averaged 53mph
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document.write( " for the first part of the trip and 59mph
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document.write( " for the second part. If the trip took 3.5
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document.write( " hours, how long did he travel at each rate? \n" );
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Algebra.Com's Answer #839949 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! You can arrange the described information this way: \n" ); document.write( " \r\n" ); document.write( " (hiour) (miles)\r\n" ); document.write( " SPEED TIME DISTANCE\r\n" ); document.write( "\r\n" ); document.write( "part one 53\r\n" ); document.write( "\r\n" ); document.write( "part two 59\r\n" ); document.write( "\r\n" ); document.write( "TOTAL 3.5 200.5\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A variable can be used and the other information can be made like here: \n" ); document.write( " \r\n" ); document.write( " (hiour) (miles)\r\n" ); document.write( " SPEED TIME DISTANCE\r\n" ); document.write( "\r\n" ); document.write( "part one 53 3.5-x 53(3.5-x)\r\n" ); document.write( "\r\n" ); document.write( "part two 59 x 59x\r\n" ); document.write( "\r\n" ); document.write( "TOTAL 3.5 200.5\r\n" ); document.write( " \n" ); document.write( "Use that and continue.... \n" ); document.write( " |