document.write( "Question 1203962: If \"+cos%28beta%29+=+-3+%2F+5+\" then, without a calculator, find \"cos%28pi+%2F+2+-+beta%29+\". Write your answer as a fraction. \n" ); document.write( "
Algebra.Com's Answer #839910 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "If \"+cos%28beta%29+=+-3+%2F+5+\" then, without a calculator, find \"cos%28pi+%2F+2+-+beta%29+\". Write your answer as a fraction.\r
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\n" ); document.write( "\n" ); document.write( "use identity: \r
\n" ); document.write( "\n" ); document.write( "\"cos%28pi%2F2+-+beta%29+=sin%28beta%29\"\r
\n" ); document.write( "\n" ); document.write( "and \r
\n" ); document.write( "\n" ); document.write( "\"sin%28beta%29=sqrt%281-cos%5E2%28beta%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "given that\r
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\n" ); document.write( "\n" ); document.write( "\"cos%28beta%29+=+-3+%2F+5+\", then\r
\n" ); document.write( "\n" ); document.write( "\"cos%5E2%28beta%29+=%28+-3+%2F+5%29%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "\"cos%5E2%28beta%29+=9+%2F25+\"\r
\n" ); document.write( "\n" ); document.write( "substitute in \"sin%28beta%29=sqrt%281-cos%5E2%28beta%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"sin%28beta%29=sqrt%281-9+%2F25+%29\"\r
\n" ); document.write( "\n" ); document.write( "\"sin%28beta%29=sqrt%2816%2F25+%29\"\r
\n" ); document.write( "\n" ); document.write( "\"sin%28beta%29=4%2F5+\" or \"sin%28beta%29=+-4%2F5+\"\r
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\n" ); document.write( "\n" ); document.write( "so, \"cos%28pi+%2F+2+-+beta%29+=4%2F5+\" or \"cos%28pi+%2F+2+-+beta%29+=+-4%2F5+\"\r
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