document.write( "Question 1203961: If then, without a calculator, find
. Write your answer as a fraction. \n" );
document.write( "
Algebra.Com's Answer #839906 by math_tutor2020(3817) ![]() You can put this solution on YOUR website! \n" ); document.write( "List of common trig identities \n" ); document.write( "https://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The identity we'll be using is \n" ); document.write( " \n" ); document.write( "it is found at the bottom of page 2 under the subsection \"Cofunction Formulas\".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Cotangent is the reciprocal of tangent, meaning that if tan(x) = 4/5, then cot(x) = 5/4. \n" ); document.write( "This then leads back to \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here is another approach.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Draw out a right triangle with these properties: \n" ); document.write( "opposite = 4 \n" ); document.write( "adjacent = 5 \n" ); document.write( "theta = reference angle\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We are then effectively given that tan(theta) = 4/5 \n" ); document.write( "The expression \n" ); document.write( "This is because the two acute angles add to pi/2 radians (aka 90 degrees). The acute angles are complementary.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "With reference to angle \n" ); document.write( "This will mean that we have: \n" ); document.write( "opposite = 5 \n" ); document.write( "adjacent = 4 \n" ); document.write( "pi/2 - theta = reference angle\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, tan(pi/2 - theta) = opposite/adjacent = 5/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here is a diagram of what I refer to \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |