document.write( "Question 1203892: Let X be a continuous random variable with density function
\n" ); document.write( "f(x) = { theta*x + 3/2*theta^{3/2}*x^2, for 0 < x < 1/sqrt( theta ); 0, otherwise }
\n" ); document.write( "where theta > 0. What is the expected value of X?
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Algebra.Com's Answer #839870 by math_tutor2020(3816)\"\" \"About 
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\n" ); document.write( "To find the expected value, we apply the integral to x*f(x) over the limits from -infinity to infinity.\r
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\n" ); document.write( "\n" ); document.write( "E(x) = expected value
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\n" ); document.write( "\n" ); document.write( "Because much of the real number line makes f(x) = 0, we only need to worry about the interval \"0+%3C+x+%3C+1%2F%28sqrt%28theta%29%29\" which is the same as \"0+%3C+x+%3C+sqrt%281%2Ftheta%29\" where theta > 0\r
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\n" ); document.write( "\n" ); document.write( "The goal has been reduced to computing
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\n" ); document.write( "\n" ); document.write( "Using fairly elementary calculus integration rules, you should find that:
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\n" ); document.write( "For some constant C.\r
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\n" ); document.write( "\n" ); document.write( "Then,
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\n" ); document.write( "\n" ); document.write( "Subtract the two results to find
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\n" ); document.write( "\n" ); document.write( "Therefore, the expected value is where theta > 0
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