document.write( "Question 1203935: At an awards ceremony, nine women and seven men are each to receive an award and are to be presented with their award one at a time. Two of the awards are to be first given to two of the women, and then the remaining awards will alternate between men and women. How many ways can this be done?
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Algebra.Com's Answer #839862 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "There are \"9\" women to choose from, and need to select \"2\" of them. \r
\n" ); document.write( "\n" ); document.write( "\"C%289%2C2%29+=+9%21+%2F+%282%21%2A%289+-+2%29%21%29+=+36\" ways\r
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\n" ); document.write( "\n" ); document.write( " After the first two awards are given to women, there will be \"7\" men and \"7\" women left to receive awards.\r
\n" ); document.write( "\n" ); document.write( "So, the total number of ways\r
\n" ); document.write( "\n" ); document.write( "\"C%2814%2C7%29+=+%2814%21%29%2F%287%21%2A+7%21%29=3432\"\r
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\n" ); document.write( "\n" ); document.write( "Now, the total number of ways:\r
\n" ); document.write( "\n" ); document.write( "Total ways \"C%289%2C2%29%2AC%2814%2C7%29+=+36+%2A+%2814%21%29%2F%287%21%2A+7%21%29=36%2A3432=123552\"\r
\n" ); document.write( "\n" ); document.write( "Therefore, there are \"123552+\"ways.\r
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