document.write( "Question 1203897: A manufacturer produces a commodity where the length of the commodity has approximately normal distribution with a mean of 7.8 inches and standard deviation of 2.6 inches. If a sample of 49 items are chosen at random, what is the probability the sample's mean length is greater than 8.8 inches? Round answer to four decimal places. \n" ); document.write( "
Algebra.Com's Answer #839826 by Theo(13342)\"\" \"About 
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population mean = 7.8
\n" ); document.write( "population standard deviation = 2.6
\n" ); document.write( "sample size = 49
\n" ); document.write( "sample mean = 8.8\r
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\n" ); document.write( "\n" ); document.write( "standard error = population standard deviation / sqrt(sample size) = 2.6 / sqrt(49) = .37143.\r
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\n" ); document.write( "\n" ); document.write( "use z = (x-m)/s formula.
\n" ); document.write( "z = z-score
\n" ); document.write( "x is sample mean
\n" ); document.write( "m = population mean
\n" ); document.write( "s = standard error\r
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\n" ); document.write( "\n" ); document.write( "formula becomes z = (8.8-7.8)/.37143 = 2.692297.\r
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\n" ); document.write( "\n" ); document.write( "area to the right of that z-score = .003548.
\n" ); document.write( "round to .0035.
\n" ); document.write( "there is a 3.5% probability that the z-score wil be more than 8.8.\r
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\n" ); document.write( "\n" ); document.write( "here's what the results look like using the calculator at https://davidmlane.com/hyperstat/z_table.html\r
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\n" ); document.write( "\n" ); document.write( "the calculator can do it from the z-score or the raw score.
\n" ); document.write( "if z-score, mean = 0 and standard deviation = 1.
\n" ); document.write( "if raw score, mean = 7.8 and standard deviation = standard error of .37143.\r
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