document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=115342>Question 115342</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Along the way to the new location- you find that all the temperatures provided are in °F. You will now continue your observations- that you had done previously. To do so, you will need to solve a linear equation. The linear equation that relates °C to °F is as follows:\r<BR>\n" );
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document.write( "°F = 1.8 °C + 32.0\r<BR>\n" );
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document.write( "The following data was calculated in this way: \r<BR>\n" );
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document.write( "Temperature °F  Miles east from starting point  <BR>\n" );
document.write( "85.2                        0<BR>\n" );
document.write( "84.5                        15<BR>\n" );
document.write( "83.6                        25<BR>\n" );
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document.write( " Provide a plot of temperature versus distance east<BR>\n" );
document.write( "Use the graph to determine the expected temperature at 75 miles east\r<BR>\n" );
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document.write( "I am completely lost on this problem, I know how to make a graph but I don't understand what they are asking for... could someone give me a little insight in solving this problem.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83982 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83982\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here's my interpretation of what you are being asked to do:<BR>\n" );
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document.write( "Because you are to \"continue your observations that you had done previously\" and are told<BR>\n" );
document.write( "that you will need to solve the linear equation that relates degrees Celsius to degrees F,<BR>\n" );
document.write( "it sounds as if previously you gathered Celsius temperatures. Furthermore it sounds as<BR>\n" );
document.write( "if you need to convert those temperatures to degrees F by plugging them into the given equation.<BR>\n" );
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document.write( "Here's a sample calculation to demonstrate the use of the equation. Suppose you previously<BR>\n" );
document.write( "found a temperature of 22 degrees C. You would convert that to degrees F by starting with:<BR>\n" );
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document.write( "F = 1.8C + 32<BR>\n" );
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document.write( "Substitute 22 for C and the equation becomes:<BR>\n" );
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document.write( "F = (1.8)(22) + 32<BR>\n" );
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document.write( "Multiply 1.8 times 22 you get 39.6 making the equation become:<BR>\n" );
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document.write( "F = 39.6 + 32<BR>\n" );
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document.write( "Add the two terms on the right side and you have 71.6. This tells you that 22 degrees C<BR>\n" );
document.write( "is equal to 71.6 degrees F.<BR>\n" );
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document.write( "You may have to do that to your previous temperatures if they are in degrees C because<BR>\n" );
document.write( "you will be making a graph in degrees F.  <BR>\n" );
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document.write( "The data you are given are:<BR>\n" );
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document.write( "85.2 degrees F at 0 miles east from the starting point<BR>\n" );
document.write( "84.5 degrees F at 15 miles east from the starting point<BR>\n" );
document.write( "83.6 degrees F at 25 miles east from the starting point<BR>\n" );
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document.write( "You are to graph these three points and the words \"temperature versus distance east\" tells <BR>\n" );
document.write( "you to make a graph showing distance on the x-axis and temperature on the y-axis.<BR>\n" );
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document.write( "Label the x-axis in miles starting at 0 (the origin) and going out to somewhat more than <BR>\n" );
document.write( "75 miles. This marking on the positive side of the x-axis represents miles east of the <BR>\n" );
document.write( "starting point.<BR>\n" );
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document.write( "On the y-axis you need to concentrate on a temperature range of around 90 degrees F down <BR>\n" );
document.write( "maybe 75 degrees F. Therefore you may want to indicate a \"break\" in the y-axis between<BR>\n" );
document.write( "the origin (0 degrees F) and 75 degrees F so that you can expand the scale of temperatures enough<BR>\n" );
document.write( "to permit your graph to show temperatures down to tenths of a degree. (Hope this makes sense<BR>\n" );
document.write( "to you because if you plot all the temperatures from 0 to 90 degrees F up the y-axis you<BR>\n" );
document.write( "will have a difficult time showing the difference between 85.2 degrees and 84.5 degrees and<BR>\n" );
document.write( "you will lose valuable detail.)<BR>\n" );
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document.write( "Go to zero on the x-axis. Then go up to 85.2 degrees F and mark that point.<BR>\n" );
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document.write( "Next go to 15 on the x-axis and go up to 84.5 degrees F and mark that point.<BR>\n" );
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document.write( "Finally go to 25 on the x-axis and then up to 83.6 degrees and mark that point.<BR>\n" );
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document.write( "(I'm not sure, but you may need to plot data that were taken or given earlier<BR>\n" );
document.write( "from other <BR>\n" );
document.write( "measurements or earlier data that you were given. This would be the data in degrees <BR>\n" );
document.write( "Celsius that you used the conversion equation to change to degrees F.)<BR>\n" );
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document.write( "Notice that the data you have plotted shows that the further east you go, the more the<BR>\n" );
document.write( "temperature drops. Take a straight edge and draw a \"best fit\" line that runs through the<BR>\n" );
document.write( "three points that you have plotted. (If you have plotted additional data points from previous<BR>\n" );
document.write( "readings, you may want to consider them also in trying to determine the \"best fit\" line.)<BR>\n" );
document.write( "By a \"best fit\" line I mean that if the data points are not in a straight line, you draw<BR>\n" );
document.write( "a line that sort of runs down the middle of the points, establishing a trend and having<BR>\n" );
document.write( "about an equal number of points above the line as below the line ... ignoring any data<BR>\n" );
document.write( "points that are obviously far away from the general trend of the data. This \"best fit\"<BR>\n" );
document.write( "line is the plot you were asked to find.<BR>\n" );
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document.write( "Make sure your \"best fit\" line runs to the right enough so that it is extends out to about <BR>\n" );
document.write( "80 miles on the x-axis. This is because you are asked to determine what temperature <BR>\n" );
document.write( "you might expect to find at 75 miles to the east of the starting point. To do that you<BR>\n" );
document.write( "would go to 75 miles on the x-axis, then go up to the line and at that intersection<BR>\n" );
document.write( "find the corresponding temperature on the y-axis. I would expect that you would get an<BR>\n" );
document.write( "answer somewhere around 80.4 degrees or so ... depending on how you place the \"best fit\"<BR>\n" );
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document.write( "Hope this gives you enough insight into the problem that you can work your way through it.<BR>\n" );
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