document.write( "Question 1203891: The local theater group anticipates that it can sell about 450 adult tickets and 700 student tickets for an upcoming show. The price of adult tickets will be $3 more than the price of student tickets. How much should each ticket cost if they intend to take in $9,400 from ticket sales? \n" ); document.write( "
Algebra.Com's Answer #839798 by greenestamps(13209)\"\" \"About 
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\n" ); document.write( "The 450 adult tickets, each costing $3 more than a student ticket, bring in an \"additional\" 450($3) = $1350.

\n" ); document.write( "So the total of $9400 can be thought of as 450+700 = 1150 tickets costing the same amount, plus the additional $1350. That means the 1150 tickets that each cost the same sell for a total of $9400-$1350 = $8050. The cost for each of them is then $8050/1150 = $7.

\n" ); document.write( "ANSWER: The student tickets should cost $7 each, the adult tickets $7+$3 = $10 each.

\n" ); document.write( "Solving the problem in exactly the same way using formal algebra looks like this:

\n" ); document.write( "x = cost of a student ticket
\n" ); document.write( "x+3 = cost of an adult ticket

\n" ); document.write( "700(x)+450(x+3) = 9400
\n" ); document.write( "700x+450x+1350 = 9400
\n" ); document.write( "1150x = 8050
\n" ); document.write( "x = 8050/1150 = 7

\n" ); document.write( "Student ticket cost: x = $7
\n" ); document.write( "Adult ticket cost: x+3 = $10

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