document.write( "Question 1203895: There are 6 quarters in a jar. Jill adds 2 quarters to the jar every day.
\n" ); document.write( "Which linear equation represents the total amount of quarters in the jar after x days?
\n" ); document.write( "Responses
\n" ); document.write( "6y = 2x
\n" ); document.write( "y = 6x + 2
\n" ); document.write( "y = 2x + 6
\n" ); document.write( "y=1/6x+2
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Algebra.Com's Answer #839792 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Answer: y = 2x + 6\r
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\n" ); document.write( "\n" ); document.write( "Reason:\r
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\n" ); document.write( "\n" ); document.write( "The equation is in y = mx+b form
\n" ); document.write( "m = 2 = slope
\n" ); document.write( "b = 6 = y intercept \r
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\n" ); document.write( "\n" ); document.write( "The slope tells us how much the coin count increases. In this case, it's 2 quarters per day.
\n" ); document.write( "The y intercept is the starting coin count. \r
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\n" ); document.write( "\n" ); document.write( "If x = 0, then,
\n" ); document.write( "y = 2x + 6
\n" ); document.write( "y = 2*0 + 6
\n" ); document.write( "y = 6
\n" ); document.write( "There are y = 6 quarters after x = 0 days (i.e. the starting day).\r
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\n" ); document.write( "\n" ); document.write( "If x = 1, then,
\n" ); document.write( "y = 2x + 6
\n" ); document.write( "y = 2*1 + 6
\n" ); document.write( "y = 8
\n" ); document.write( "There are y = 8 quarters after x = 1 day \r
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\n" ); document.write( "\n" ); document.write( "If x = 2, then,
\n" ); document.write( "y = 2x + 6
\n" ); document.write( "y = 2*2 + 6
\n" ); document.write( "y = 10
\n" ); document.write( "There are y = 10 quarters after x = 2 days
\n" ); document.write( "And so on.
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