document.write( "Question 1203895: There are 6 quarters in a jar. Jill adds 2 quarters to the jar every day.
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document.write( "Which linear equation represents the total amount of quarters in the jar after x days?
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document.write( "Responses
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document.write( "6y = 2x
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document.write( "y = 6x + 2
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document.write( "y = 2x + 6
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document.write( "y=1/6x+2 \n" );
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Algebra.Com's Answer #839792 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: y = 2x + 6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Reason:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The equation is in y = mx+b form \n" ); document.write( "m = 2 = slope \n" ); document.write( "b = 6 = y intercept \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The slope tells us how much the coin count increases. In this case, it's 2 quarters per day. \n" ); document.write( "The y intercept is the starting coin count. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If x = 0, then, \n" ); document.write( "y = 2x + 6 \n" ); document.write( "y = 2*0 + 6 \n" ); document.write( "y = 6 \n" ); document.write( "There are y = 6 quarters after x = 0 days (i.e. the starting day).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If x = 1, then, \n" ); document.write( "y = 2x + 6 \n" ); document.write( "y = 2*1 + 6 \n" ); document.write( "y = 8 \n" ); document.write( "There are y = 8 quarters after x = 1 day \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If x = 2, then, \n" ); document.write( "y = 2x + 6 \n" ); document.write( "y = 2*2 + 6 \n" ); document.write( "y = 10 \n" ); document.write( "There are y = 10 quarters after x = 2 days \n" ); document.write( "And so on. \n" ); document.write( " \n" ); document.write( " |