document.write( "Question 1203888: you can afford $1,500 per month mortgage payment. you've found a 30 years loan at 6% interest a) how big of a loan can you afford b)how much total money will you pay the loan company c) how much of that money is interest \n" ); document.write( "
Algebra.Com's Answer #839773 by math_tutor2020(3817) ![]() You can put this solution on YOUR website! \n" ); document.write( "Answers: \n" ); document.write( "(a) $250,187.42 \n" ); document.write( "(b) $540,000 \n" ); document.write( "(c) $289,812.58\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "====================================================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation for part (a)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Monthly payment formula \n" ); document.write( "P = (L*i)/( 1-(1+i)^(-n) ) \n" ); document.write( "where, \n" ); document.write( "P = monthly payment \n" ); document.write( "L = loan amount \n" ); document.write( "i = monthly interest rate in decimal form \n" ); document.write( "n = number of months\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For this problem: \n" ); document.write( "P = 1500 \n" ); document.write( "L = unknown \n" ); document.write( "i = 0.06/12 = 0.005 exactly \n" ); document.write( "n = 30*12 = 360 months\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's solve for L \n" ); document.write( "P = (L*i)/( 1-(1+i)^(-n) ) \n" ); document.write( "1500 = (L*0.005)/( 1-(1+0.005)^(-360) ) \n" ); document.write( "1500 = 0.00599550525152L \n" ); document.write( "L = 1500/0.00599550525152 \n" ); document.write( "L = 250,187.421588817 \n" ); document.write( "L = 250,187.42\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The largest loan you can afford is $250,187.42\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------\r \n" ); document.write( "\n" ); document.write( "Explanation for part (b)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Over the course of 360 months (aka 30 years), you pay $1500 a month. \n" ); document.write( "This assumes you go with the max you can afford.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "360*($1500) = $540,000 is the amount paid back. \n" ); document.write( "This consists of the principal (aka loan amount) of $250,187.42 calculated back in part (a), and also consists of interest as well.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------\r \n" ); document.write( "\n" ); document.write( "Explanation for part (c)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract the results of parts (a) and (b) to compute the total interest.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "interest = (total amount paid back) - (loan amount) \n" ); document.write( "interest = ($540,000) - ($250,187.42) \n" ); document.write( "interest = $289,812.58 \n" ); document.write( " \n" ); document.write( " |