document.write( "Question 1203803: A discrete random variable has pdf f(x).
\n" ); document.write( "(a) If f(x) = k(1/2)^x for x= 1, 2, 3, and zero otherwise, find k.
\n" ); document.write( "(b) Is a function of the form f(x) = k[(1/2)^x - 1/2] for x = 0, 1, 2 a pdf for any k?
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Algebra.Com's Answer #839764 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Part (a)\r
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\n" ); document.write( "\n" ); document.write( "f(x) = k(1/2)^x
\n" ); document.write( "f(1) = k(1/2)^1
\n" ); document.write( "f(1) = k/2\r
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\n" ); document.write( "\n" ); document.write( "f(x) = k(1/2)^x
\n" ); document.write( "f(2) = k(1/2)^2
\n" ); document.write( "f(2) = k/4\r
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\n" ); document.write( "\n" ); document.write( "f(x) = k(1/2)^x
\n" ); document.write( "f(3) = k(1/2)^3
\n" ); document.write( "f(3) = k/8\r
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\n" ); document.write( "\n" ); document.write( "For any PDF, the f(x) probability values add to 1.\r
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\n" ); document.write( "\n" ); document.write( "f(1) + f(2) + f(3) = 1
\n" ); document.write( "k/2 + k/4 + k/8 = 1
\n" ); document.write( "4k/8 + 2k/8 + k/8 = 1
\n" ); document.write( "(4k+2k+k)/8 = 1
\n" ); document.write( "7k/8 = 1
\n" ); document.write( "7k = 1*8
\n" ); document.write( "7k = 8
\n" ); document.write( "k = 8/7\r
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\n" ); document.write( "\n" ); document.write( "=========================================\r
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\n" ); document.write( "\n" ); document.write( "Part (b)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "f(x) = k[(1/2)^x - 1/2]
\n" ); document.write( "f(0) = k[(1/2)^0 - 1/2]
\n" ); document.write( "f(0) = k/2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "f(x) = k[(1/2)^x - 1/2]
\n" ); document.write( "f(1) = k[(1/2)^1 - 1/2]
\n" ); document.write( "f(1) = 0\r
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\n" ); document.write( "\n" ); document.write( "f(x) = k[(1/2)^x - 1/2]
\n" ); document.write( "f(2) = k[(1/2)^2 - 1/2]
\n" ); document.write( "f(2) = -k/4\r
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\n" ); document.write( "\n" ); document.write( "f(0)+f(1)+f(2) = 1
\n" ); document.write( "k/2 + 0 + (-k/4) = 1
\n" ); document.write( "2k/4 - k/4 = 1
\n" ); document.write( "(2k-k)/4 = 1
\n" ); document.write( "k/4 = 1
\n" ); document.write( "k = 4\r
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\n" ); document.write( "\n" ); document.write( "f(x) is a PDF if and only if k = 4
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