document.write( "Question 1203846: Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following probability, given the number of trials and the probability of obtaining a success. Round your answer to four decimal places.\r
\n" ); document.write( "\n" ); document.write( "P(X<5), n=7, p=0.3
\n" ); document.write( "

Algebra.Com's Answer #839714 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"+P%28X%3C5%29\", \"+n=7\", \"+p=0.3\"\r
\n" ); document.write( "\n" ); document.write( "What is binomial distribution?
\n" ); document.write( "In binomial distribution for number trials we are investigating the probability of getting a success remain the same.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"+n+\"= number of trails,
\n" ); document.write( "\"+p\" = probability of success
\n" ); document.write( "\"+x\" = the number of success\r
\n" ); document.write( "\n" ); document.write( "given that \"+P%28x%3C5%29\", so use \"+x\"=\"0\",\"1\",\"2\",\"3\",\"4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"+p%28x%3C5%29=p%28x=0%29%2Bp%28x=1%29%2B+p%28x=2%29%2Bp%28x=3%29%2Bp%28x=4%29\"\r
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "\n" ); document.write( "\"+p%28x%3C5%29=0.0823543%2B0.2470629%2B0.3176523%2B0.2268945%2B0.0972405\"\r
\n" ); document.write( "\n" ); document.write( "\"+p%28x%3C5%29=0.9712045\"
\n" ); document.write( "\"+p%28x%3C5%29=0.9712\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );