document.write( "Question 1203823: Find all exact solutions on [0, 2𝜋). (Enter your answers as a comma-separated list.)
\n" ); document.write( "2 cos^2(t) − cos(t) = 1
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Algebra.Com's Answer #839669 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Let w = cos(t)\r
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\n" ); document.write( "\n" ); document.write( "The original equation
\n" ); document.write( "2cos^2(t) - cos(t) = 1
\n" ); document.write( "turns into
\n" ); document.write( "2w^2 - w = 1
\n" ); document.write( "and rearranges into
\n" ); document.write( "2w^2 - w - 1 = 0\r
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\n" ); document.write( "\n" ); document.write( "Use the quadratic formula, or factoring, to find the roots are:
\n" ); document.write( "w = -1/2 or w = 1\r
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\n" ); document.write( "\n" ); document.write( "This leads us back to
\n" ); document.write( "cos(t) = -1/2 or cos(t) = 1\r
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\n" ); document.write( "\n" ); document.write( "Then use the unit circle to find that cos(t) = -1/2 has the solutions: t = 2pi/3 and t = 4pi/3
\n" ); document.write( "In other words,
\n" ); document.write( "cos(2pi/3) = -1/2 and cos(4pi/3) = -1/2 when your calculator is set to radian mode.\r
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\n" ); document.write( "\n" ); document.write( "Use the unit circle to find the solutions to cos(t) = 1 are: t = 0 and t = 2pi
\n" ); document.write( "However, we exclude 2pi due to the interval \"0+%3C=+t+%3C+2pi\" which condenses to the interval notation [0, 2pi)\r
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\n" ); document.write( "\n" ); document.write( "You can use a graphing calculator such as a TI83/TI84, Desmos, or GeoGebra to confirm these answers.
\n" ); document.write( "The function to plot would be f(x) = 2*(cos(x))^2 - cos(x) - 1
\n" ); document.write( "The goal is to look for the x intercepts on the interval \"0+%3C=+x+%3C+2pi\"
\n" ); document.write( "Note that
\n" ); document.write( "2pi/3 = 2.094395 approximately
\n" ); document.write( "4pi/3 = 4.188790 approximately\r
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\n" ); document.write( "\n" ); document.write( "Answers: 0, 2pi/3, 4pi/3
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