document.write( "Question 1203824: decide what values of the variable cannot possibly be solutions for the equation. 1/x-3 + 1/x+2 = 1/x^2-x-6 \n" ); document.write( "
Algebra.Com's Answer #839665 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "decide what values of the variable cannot possibly be solutions for the equation\r
\n" ); document.write( "\n" ); document.write( "\"1%2F%28x-3+%29%2B+1%2F%28x%2B2+%29=+1%2F%28x%5E2-x-6%29\"\r
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\n" ); document.write( "\n" ); document.write( "since denominator cannot be equal to zero, the values of the variable cannot possibly be solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"%28x+%2B+2%29+=0\"=> \"x=-2\"
\n" ); document.write( "or
\n" ); document.write( "\"%28x+-+3%29=0\"=> \"x=3\"\r
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