document.write( "Question 1203815: Three machines turn out all the products in a factory, with the first machine producing 10% of the products, the second machine 15%, and the third machine 75%. The first machine produces defective products 6% of the time, the second machine 15% of the time and the third machine 8% of the time. What is the probability that a non-defective product came from the second machine? (Round your answer to four decimal places. \n" ); document.write( "

Algebra.Com's Answer #839663 by ikleyn(52778) $\"\"$ $\"About$

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\n" ); document.write( "Three machines turn out all the products in a factory, with the first machine
\n" ); document.write( "producing 10% of the products, the second machine 15%, and the third machine 75%.
\n" ); document.write( "The first machine produces defective products 6% of the time, the second machine 15% of the time
\n" ); document.write( "and the third machine 8% of the time. What is the probability that a non-defective product
\n" ); document.write( "came from the second machine? (Round your answer to four decimal places.
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document.write( "It is about calculating a conditional probability.\r\n" );
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document.write( "This conditional probability is the fraction, whose denominator is the probability\r\n" );
document.write( "to get a non-defective product from all 3 machines, while the numerator\r\n" );
document.write( "is the probability to get a non-defective product from second machine.\r\n" );
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document.write( "By knowing it, we write the formula immediately\r\n" );
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document.write( "    P =  = 0.1399  (rounded as requested).\r\n" );
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document.write( "ANSWER.  P = 0.1399  (rounded as requested).\r\n" );
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