document.write( "Question 115373: for the hawks' 80 basketball games next year, you can buy seperate tickets for each game at $9 each, or you can buy a season ticket for $580. at most how many games could you attend at the $9 price before spending more than the cost of a season ticket? \r
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Algebra.Com's Answer #83966 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
If you attend one game it costs $9. If you attend 2 games it costs you $18. If you attend 3
\n" ); document.write( "games it costs you $27. And so on.
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\n" ); document.write( "This leads you to ask yourself how many times $9 goes into $580, and this is a division
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\n" ); document.write( "Divide $9 into $580 and you find that it goes 64 times with a remainder of $4. This means
\n" ); document.write( "that at $9 per ticket you could go to 64 games before you didn't have enough money left to
\n" ); document.write( "buy another ticket. If you attended a 65th game you would have spent a total of $585 and this
\n" ); document.write( "is $5 more than the cost of a season ticket.
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\n" ); document.write( "Hope this helps you to understand the problem a little better.
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