document.write( "Question 1203779: There is roughly an 80% chance that a person of age 20 will be alive at 65 suppose that 3 age 20's are selected at random. Find the probability that the number alive at 65 will be exactly two(2)
\n" ); document.write( "b) Atleast one
\n" ); document.write( "c) Atmost two
\n" ); document.write( "d) Less than one
\n" ); document.write( "e) Write the probability distribution
\n" ); document.write( "

Algebra.Com's Answer #839627 by greenestamps(13209)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "The logical way to answer these questions is to do part (e) first and -- to verify that your calculations are correct -- verify that the sum of the probabilities is 1; then answer the individual questions.

\n" ); document.write( "********
\n" ); document.write( "NOTE!\r
\n" ); document.write( "\n" ); document.write( "If you are just learning how to calculate binomial probabilities, it is good practice -- if the number of cases is small -- to calculate the probabilities of all possible outcomes and verify that their sum is 1\r
\n" ); document.write( "\n" ); document.write( "********

\n" ); document.write( "3 of 3 alive at age 65:
\n" ); document.write( "\"C%283%2C3%29%28%28.8%29%5E3%29%28%28.2%29%5E0%29=%281%29%28.512%29%281%29=.512\"

\n" ); document.write( "2 of 3 alive at age 65:
\n" ); document.write( "\"C%283%2C2%29%28%28.8%29%5E2%29%28%28.2%29%5E1%29=%283%29%28.64%29%28.2%29=.384\"

\n" ); document.write( "1 of 3 alive at age 65:
\n" ); document.write( "\"C%283%2C1%29%28%28.8%29%5E1%29%28%28.2%29%5E2%29=%283%29%28.8%29%28.04%29=.096\"

\n" ); document.write( "0 of 3 alive at age 65:
\n" ); document.write( "\"C%283%2C0%29%28%28.8%29%5E0%29%28%28.2%29%5E3%29=%281%29%281%29%28.008%29=.008\"

\n" ); document.write( ".512+.384+.096+.008 = 1.000 so the calculations should be good.

\n" ); document.write( "ANSWERS:
\n" ); document.write( "(a) exactly 2: 0.384
\n" ); document.write( "(b) at least 1: 1-.008 = 0.992
\n" ); document.write( "(c) at most 2: 1-.512 = 0.488
\n" ); document.write( "(d) less than 1: 0.008
\n" ); document.write( "(e) (see above)

\n" ); document.write( "
\n" ); document.write( "
\n" );