document.write( "Question 1203779:  There is roughly an 80% chance that a person of age 20 will be alive at 65 suppose that 3 age 20's are selected at random. Find the probability that the number alive at 65 will be exactly two(2)
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document.write( "b) Atleast one 
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document.write( "c) Atmost two
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document.write( "d) Less than one 
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document.write( "e) Write the probability distribution \n" );
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| Algebra.Com's Answer #839627 by greenestamps(13209)     You can put this solution on YOUR website! \n" ); document.write( "The logical way to answer these questions is to do part (e) first and -- to verify that your calculations are correct -- verify that the sum of the probabilities is 1; then answer the individual questions. \n" ); document.write( "******** \n" ); document.write( "NOTE!\r \n" ); document.write( "\n" ); document.write( "If you are just learning how to calculate binomial probabilities, it is good practice -- if the number of cases is small -- to calculate the probabilities of all possible outcomes and verify that their sum is 1\r \n" ); document.write( "\n" ); document.write( "******** \n" ); document.write( "3 of 3 alive at age 65: \n" ); document.write( " \n" ); document.write( "2 of 3 alive at age 65: \n" ); document.write( " \n" ); document.write( "1 of 3 alive at age 65: \n" ); document.write( " \n" ); document.write( "0 of 3 alive at age 65: \n" ); document.write( " \n" ); document.write( ".512+.384+.096+.008 = 1.000 so the calculations should be good. \n" ); document.write( "ANSWERS: \n" ); document.write( "(a) exactly 2: 0.384 \n" ); document.write( "(b) at least 1: 1-.008 = 0.992 \n" ); document.write( "(c) at most 2: 1-.512 = 0.488 \n" ); document.write( "(d) less than 1: 0.008 \n" ); document.write( "(e) (see above) \n" ); document.write( " \n" ); document.write( " |