document.write( "Question 1203782: 𝐸 is the midpoint of 𝐷F. 𝐷𝐸 = 4π‘₯ + 3
\n" ); document.write( "and 𝐸𝐹 = 8π‘₯ βˆ’ 9. Find 𝐷𝐸, 𝐸𝐹, and 𝐷�
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Algebra.Com's Answer #839611 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "if \"+E\" is the midpoint of \"+DF\", then \"+DE=EF\"\r
\n" ); document.write( "\n" ); document.write( "if\r
\n" ); document.write( "\n" ); document.write( "\"+DE+=+4x+%2B+3\"
\n" ); document.write( "\"+EF+=+8x+-+9\"\r
\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( "\"+4x+%2B+3=8x+-+9\"
\n" ); document.write( "\"+9%2B+3=8x+-4x+\"
\n" ); document.write( "\"+12=4x+\"
\n" ); document.write( "\"+x=3\"\r
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\n" ); document.write( "\n" ); document.write( "so,\r
\n" ); document.write( "\n" ); document.write( "\"+DE+=+4x+%2B+3=4%2A3%2B3=15\"
\n" ); document.write( "since\"+DE=EF\", we have \"EF+=15\"\r
\n" ); document.write( "\n" ); document.write( "\"+DE=EF%2BDF=DE%2BEF+=15%2B15=30\"\r
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