document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1203761>Question 1203761</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of c and YZ if Y is between X and Z.\r<BR>\n" );
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document.write( "XY=11, YZ=4c, XZ=83 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #839582 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=839582\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "Since Y is in between X & Z\r<BR>\n" );
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document.write( "seg XY + seg YZ = seg XZ   ( segment addition property\r<BR>\n" );
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document.write( "XY=11, YZ=4c, XZ=83\r<BR>\n" );
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document.write( "11+4c= 83\r<BR>\n" );
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document.write( "subtract 11<BR>\n" );
document.write( "4c = 83-11<BR>\n" );
document.write( "4c =  72<BR>\n" );
document.write( "c = 18<BR>\n" );
document.write( "YZ=4c =72\r<BR>\n" );
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