document.write( "Question 1203740: 5.) The sum of the ages of Ace, Sabo, and Luffy is 27. Three years from now will be 4 times as old as Ace. IfL Uffy was twice as old as Ace 3 years ago, how old are they now? \n" ); document.write( "
Algebra.Com's Answer #839567 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "Although there is a hole in your statement of the problem, logical reasoning leads to only one possible solution.

\n" ); document.write( "But that solution is not very interesting; so probably the given information is not correct.

\n" ); document.write( "The given information tells us that Luffy was twice as old as Ace 3 years ago, and that ?? will be 4 times as old as Ace 3 years from now. ?? can't be Luffy, because if he was only twice as old as Ace 3 years ago it is not possible for him to be 4 times as old 3 years from now.

\n" ); document.write( "So ?? must be Sabo.

\n" ); document.write( "So....

\n" ); document.write( "Let x = Ace's age 3 years ago
\n" ); document.write( "Then 2x = Luffy's age 3 years ago

\n" ); document.write( "Then x+3 is Ace's age now and 2x+3 is Luffy's age now. Since the sum of their ages is 27, Sabo's age now is 27-((x+3)+2x+3)) = 21-3x.

\n" ); document.write( "Then Ace's age 3 years from now will be x+6, and Sabo's age 3 years from now will be 24-3x.

\n" ); document.write( "3 years from now, Sabo's age will be 4 times Ace's age:

\n" ); document.write( "24-3x=4(x+6)
\n" ); document.write( "24-3x=4x+24
\n" ); document.write( "7x=0
\n" ); document.write( "x=0

\n" ); document.write( "ANSWERS (apparently...):
\n" ); document.write( "Ace's age: x+3 = 3
\n" ); document.write( "Luffy's age: 2x+3 =3
\n" ); document.write( "Sabo's age: 21-3x = 21

\n" ); document.write( "3 years ago their ages were 0, 0, and 18

\n" ); document.write( "3 years from now their ages will be 6, 6, and 24 -- satisfying the condition that Sabo will be 4 times as old as Ace then.

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