document.write( "Question 1203740: 5.) The sum of the ages of Ace, Sabo, and Luffy is 27. Three years from now will be 4 times as old as Ace. IfL Uffy was twice as old as Ace 3 years ago, how old are they now? \n" ); document.write( "
Algebra.Com's Answer #839567 by greenestamps(13203)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Although there is a hole in your statement of the problem, logical reasoning leads to only one possible solution. \n" ); document.write( "But that solution is not very interesting; so probably the given information is not correct. \n" ); document.write( "The given information tells us that Luffy was twice as old as Ace 3 years ago, and that ?? will be 4 times as old as Ace 3 years from now. ?? can't be Luffy, because if he was only twice as old as Ace 3 years ago it is not possible for him to be 4 times as old 3 years from now. \n" ); document.write( "So ?? must be Sabo. \n" ); document.write( "So.... \n" ); document.write( "Let x = Ace's age 3 years ago \n" ); document.write( "Then 2x = Luffy's age 3 years ago \n" ); document.write( "Then x+3 is Ace's age now and 2x+3 is Luffy's age now. Since the sum of their ages is 27, Sabo's age now is 27-((x+3)+2x+3)) = 21-3x. \n" ); document.write( "Then Ace's age 3 years from now will be x+6, and Sabo's age 3 years from now will be 24-3x. \n" ); document.write( "3 years from now, Sabo's age will be 4 times Ace's age: \n" ); document.write( "24-3x=4(x+6) \n" ); document.write( "24-3x=4x+24 \n" ); document.write( "7x=0 \n" ); document.write( "x=0 \n" ); document.write( "ANSWERS (apparently...): \n" ); document.write( "Ace's age: x+3 = 3 \n" ); document.write( "Luffy's age: 2x+3 =3 \n" ); document.write( "Sabo's age: 21-3x = 21 \n" ); document.write( "3 years ago their ages were 0, 0, and 18 \n" ); document.write( "3 years from now their ages will be 6, 6, and 24 -- satisfying the condition that Sabo will be 4 times as old as Ace then. \n" ); document.write( " \n" ); document.write( " |