document.write( "Question 1203746: The length of a rectangle is 3 less than twice the width. The perimeter is 36. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #839557 by Theo(13342)\"\" \"About 
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P = 2L + 2W
\n" ); document.write( "L = 2W - 3
\n" ); document.write( "P = 2 * (2W - 3) + 2W = 4W - 6 + 2W = 6W - 6
\n" ); document.write( "P = 36
\n" ); document.write( "36 = 6W - 6
\n" ); document.write( "add 6 to both sides to get:
\n" ); document.write( "42 = 6W
\n" ); document.write( "solve for W to get:
\n" ); document.write( "W = 7
\n" ); document.write( "L = 2W - 3 = 14 - 3 = 11
\n" ); document.write( "you have:
\n" ); document.write( "L = 11
\n" ); document.write( "W = 7
\n" ); document.write( "P = 2L + 2W = 22 + 14 = 36
\n" ); document.write( "solution is confirmed to be good.
\n" ); document.write( "P = the perimeter of the rectangle
\n" ); document.write( "L = the length of the rectangle.
\n" ); document.write( "W = the width of the rectangle.\r
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