document.write( "Question 1203746: The length of a rectangle is 3 less than twice the width. The perimeter is 36. Find the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #839556 by ikleyn(52858) $\"\"$ $\"About$

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document.write( "w + (2w-3) = 36/2\r\n" );
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document.write( "3w - 3 = 18\r\n" );
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document.write( "3w = 18 + 3\r\n" );
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document.write( "3w = 21\r\n" );
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document.write( " w = 21/3 = 7.\r\n" );
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document.write( "ANSWER.  The dimensions of the rectangle are 7 and 2*7 -3 = 11.\r\n" );
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document.write( "CHECK.  7 + 11 + 7 + 11 = 36   ! correct !\r\n" );
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