document.write( "Question 1203724: two number are in the ratio 3:2. if the smaller number is 24, find larger number.
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Algebra.Com's Answer #839510 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( " two number are in the ratio \"3%3A2\"\r
\n" ); document.write( "\n" ); document.write( " let the larger number be \"x\" and smaller number \"y\"\r
\n" ); document.write( "\n" ); document.write( "then we have\r
\n" ); document.write( "\n" ); document.write( "\"x%2Fy=3%2F2\"\r
\n" ); document.write( "\n" ); document.write( " if the smaller number is \"y=24\", we have\r
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\n" ); document.write( "\n" ); document.write( "\"x%2F24=3%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"x=24%283%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=12%283%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=36\"\r
\n" ); document.write( "\n" ); document.write( " larger number is \"x=36\"\r
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