document.write( "Question 1203707: Find five consecutive integers such that:\r
\n" ); document.write( "\n" ); document.write( "“The sum of the first and 4 times the third is equal to 56 less than 3 times the sum of the second, fourth, and fifth.”
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Algebra.Com's Answer #839493 by MathLover1(20850) $\"\"$ $\"About$

You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "The formula for a sequence of consecutive integers is $\"n\"$ , $\"n%2B1\"$ , $\"n%2B2\"$ , $\"+n%2B3\"$ , $\"n%2B4\"$ ,..., $\"n%2Bk\"$ .\r
\n" ); document.write( "\n" ); document.write( "The sum of the first and $\"4+\"$ times the third is equal to $\"56\"$ less than $\"3+\"$ times the sum of the second, fourth, and fifth.\r
\n" ); document.write( "\n" ); document.write( " $\"n%2B4%28n%2B2%29=3%28%28n%2B1%29%2B%28n%2B3%29%2B%28n%2B4%29%29-56\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"n%2B4n%2B8=3%283n%2B8%29-56\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"5n%2B8=9n%2B24-56\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"56%2B8-24=9n-5n\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"40=4n\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"n=10\"$ \r
\n" ); document.write( "\n" ); document.write( " five consecutive integers are: $\"10\"$ , $\"11\"$ , $\"12\"$ , $\"14\"$ , $\"14\"$ \r
\n" ); document.write( "\n" ); document.write( "check:\r
\n" ); document.write( "\n" ); document.write( " $\"10%2B4%2812%29=3%28%2811%29%2B%2813%29%2B%2814%29%29-56\"$
\n" ); document.write( " $\"10%2B48=3%2838%29-56\"$
\n" ); document.write( " $\"58=58\"$ \r
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