document.write( "Question 1203691: For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d = v + v2 20 where d is measured in feet. kerry wants her stopping distance not to exceed 40ft. at what range of speeds (in mi/h) can she travel? (enter your answer using interval notation \n" ); document.write( "
Algebra.Com's Answer #839462 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "The formula d = v + v2 20 seems strangely formed. Please double-check to make sure you typed this correctly.\r
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\n" ); document.write( "\n" ); document.write( "After some online searching, I found a similar problem with the formula \"d+=+v+%2B+%28v%5E2%29%2F20\" and the stopping distance was 240 feet (instead of 40 feet)
\n" ); document.write( "If this is the formula and stopping distance your teacher gave you, then read on. If not then let me know.\r
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\n" ); document.write( "\n" ); document.write( "d = stopping distance or braking distance = the distance the car travels when the brakes are first applied to when the car comes to a complete stop\r
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\n" ); document.write( "\n" ); document.write( "\"d+%3C=+240\"\r
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\n" ); document.write( "\n" ); document.write( "\"v+%2B+%28v%5E2%29%2F20+%3C=+240\"\r
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\n" ); document.write( "\n" ); document.write( "\"20%2A%28v+%2B+%28v%5E2%29%2F20%29+%3C=+20%2A240\"\r
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\n" ); document.write( "\n" ); document.write( "\"20v+%2B+v%5E2+%3C=+4800\"\r
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\n" ); document.write( "\n" ); document.write( "\"20v+%2B+v%5E2-4800+%3C=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"v%5E2+%2B+20v+-+4800+%3C=+0\"\r
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\n" ); document.write( "\n" ); document.write( "Let's complete the square
\n" ); document.write( "\"v%5E2+%2B+20v+-+4800+%3C=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"v%5E2+%2B+20v+%2B+0+-+4800+%3C=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"v%5E2+%2B+20v+%2B+100+-+100+-+4800+%3C=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28v%5E2+%2B+20v+%2B+100%29+-+100+-+4800+%3C=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28v%2B10%29%5E2+-+100+-+4800+%3C=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28v%2B10%29%5E2+-+4900+%3C=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28v%2B10%29%5E2+%3C=+4900\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28%28v%2B10%29%5E2%29+%3C=+sqrt%284900%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"abs%28v%2B10%29+%3C=+70\" Use the rule sqrt(x^2) = |x| \r
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\n" ); document.write( "\n" ); document.write( "\"-70+%3C=+v%2B10+%3C=+70\" we use the rule that |x| < k becomes -k < x < k, for some positive value k.\r
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\n" ); document.write( "\n" ); document.write( "\"-70-10+%3C=+v%2B10-10+%3C=+70-10\"\r
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\n" ); document.write( "\n" ); document.write( "\"-80+%3C=+v+%3C=+60\"\r
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\n" ); document.write( "\n" ); document.write( "Another way to solve would be to factor \"v%5E2+%2B+20v+-+4800+%3C=+0\" to get \"%28v%2B80%29%28v-60%29+%3C=+0\"
\n" ); document.write( "The roots are v = -80 and v = 60
\n" ); document.write( "The region between these roots will make the left hand side either 0 or negative.\r
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\n" ); document.write( "\n" ); document.write( "Clearly we cannot have negative speeds.
\n" ); document.write( "Therefore we must revise \"-80+%3C=+v+%3C=+60\" to \"0+%3C=+v+%3C=+60\"\r
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\n" ); document.write( "\n" ); document.write( "To be more technical, since she is driving, her speed cannot be zero.
\n" ); document.write( "So we further would say \"0+%3C+v+%3C=+60\"\r
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\n" ); document.write( "\n" ); document.write( "That converts to the interval notation (0, 60]
\n" ); document.write( "The parenthesis excludes the endpoint 0.
\n" ); document.write( "A square bracket is used to include the endpoint 60.\r
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\n" ); document.write( "\n" ); document.write( "Answer: (0, 60]
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