document.write( "Question 1203688: At noon, a cargo plane leaves Angama airport and heads towards Bamburi 500 km away at 180 km/h. At 1.00 pm, a jet takes off from Angama and flies on the same course at 450 km/h. What time will the jet overtake the cargo plane? \n" ); document.write( "
Algebra.Com's Answer #839457 by math_tutor2020(3816)\"\" \"About 
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\n" ); document.write( "x = number of hours since 12:00 pm noon\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Cargo Plane
\n" ); document.write( "distance = rate*time
\n" ); document.write( "d = r*t
\n" ); document.write( "d = 180x\r
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\n" ); document.write( "\n" ); document.write( "Jet Aircraft
\n" ); document.write( "d = r*t
\n" ); document.write( "d = 450(x-1)
\n" ); document.write( "The x-1 refers to the fact the jet is in the air 1 hour less compared to the cargo plane. \r
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\n" ); document.write( "\n" ); document.write( "The jet will pass the cargo plane when the two distances are equal.
\n" ); document.write( "450(x-1) = 180x
\n" ); document.write( "450x-450 = 180x
\n" ); document.write( "450x-180x = 450
\n" ); document.write( "270x = 450
\n" ); document.write( "x = 450/270
\n" ); document.write( "x = (5*90)/(3*90)
\n" ); document.write( "x = 5/3
\n" ); document.write( "x = (1+2)/3
\n" ); document.write( "x = (1/3) + (2/3)
\n" ); document.write( "x = 1 + (2/3)
\n" ); document.write( "x = 1 & 2/3\r
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\n" ); document.write( "\n" ); document.write( "1 & 2/3 hr = 1 hr + (2/3) hr
\n" ); document.write( "1 & 2/3 hr = 1 hr + (2/3)*60 min
\n" ); document.write( "1 & 2/3 hr = 1 hr + 40 min\r
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\n" ); document.write( "\n" ); document.write( "The jet will overtake the cargo plane 1 hour and 40 minutes after the cargo plane takes off.\r
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\n" ); document.write( "\n" ); document.write( "Add this duration to 12:00 pm noon to get
\n" ); document.write( "12:00 + 1:40 = 1:40 pm which is the final answer.
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