document.write( "Question 1203682: The hourly wage of some Toyota assembly line workers increased annually by the same percentage if their wage went from 7.10 to 20.08 in 12 years what is the doubling time \n" ); document.write( "
Algebra.Com's Answer #839440 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Refer to the steps tutor @Edwin has provided to determine that r = 0.09 = 9% approximately. \r
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\n" ); document.write( "\n" ); document.write( "Another approach would be to find the positive root of the function \"f%28x%29=7.10%281%2Bx%29%5E%2812%29-20.08\"
\n" ); document.write( "Use a graphing tool like a TI83/TI84, Desmos, or GeoGebra.
\n" ); document.write( "The root finding feature quickly locates the positive x intercept to be roughly x = 0.09\r
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\n" ); document.write( "\n" ); document.write( "Then we can use the rule of 72 shortcut.
\n" ); document.write( "We divide 72 over the r value, in which we have removed the percent sign. Do not use the decimal form.\r
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\n" ); document.write( "\n" ); document.write( "doubling time = 72/(r value without percent sign)
\n" ); document.write( "doubling time = 72/9
\n" ); document.write( "doubling time = 8 years\r
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\n" ); document.write( "\n" ); document.write( "This shortcut gives us an approximation rather than the exact answer.
\n" ); document.write( "But sometimes all that's needed is a good enough approximation.\r
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\n" ); document.write( "\n" ); document.write( "A more accurate doubling time formula is
\n" ); document.write( "\"t+=+%28ln%282%29%29%2F%28ln%281%2Br%29%29\"
\n" ); document.write( "where the 2 in ln(2) refers to doubling.
\n" ); document.write( "Replace 2 with 3 if you want to know how long it takes for your money to triple for instance.\r
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\n" ); document.write( "\n" ); document.write( "If r = 0.09, then we'll get the following doubling time
\n" ); document.write( "\"t+=+%28ln%282%29%29%2F%28ln%281%2Br%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28ln%282%29%29%2F%28ln%281%2B0.09%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+8.0432\" approximately, which is fairly close to t = 8 we got earlier.
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