document.write( "Question 1203653: Jay traveled from his house to his office at an average speed of 25mph. by traveling 5mph faster, he took 30 minutes less to return home. How far is Jay's office from his house \n" ); document.write( "

Algebra.Com's Answer #839393 by josgarithmetic(39617) $\"\"$ $\"About$

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document.write( "                         SPEED         TIME hours    DISTANCE each way, miles\r\n" );
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document.write( "House to Office            25           L/25           L\r\n" );
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document.write( "Office to House            25+5=30      L/30           L\r\n" );
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document.write( "DIFFERENCE                              1/2\r\n" );
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\n" ); document.write( " $\"highlight_green%28L%2F25-L%2F30=1%2F2%29\"$ \r
\n" ); document.write( "\n" ); document.write( "l.c.d., 2*5*5*3\r
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\n" ); document.write( "\n" ); document.write( " $\"%282%2A3%2A5%2A5%29%28L%2F25-L%2F30%29=%282%2A3%2A5%2A5%29%2F2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"6L-5L=75\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28L=75%29\"$ \n" ); document.write( "

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