Algebra.Com's Answer #839390 by ikleyn(52793)![\"\"](\"/images/stars/stars-13.gif\")  
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document.write( "Jay traveled from his house to his office at an average speed of 25mph.
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document.write( "by traveling 5mph faster, he took 30 minutes less to return home.
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document.write( "How far is Jay's office from his house
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document.write( "Let d be the distance from the house to the office, in miles.\r\n" );
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document.write( "Traveling at 25 mph, Jay spends  hours.\r\n" );
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document.write( "Traveling back at the speed 25 mph + 5 mph = 30 mph, he spends  hours.\r\n" );
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document.write( "The difference is 30 minutes, or  of an hour;\r\n" );
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document.write( "so we write this \"time equation\"\r\n" );
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document.write( " - = of an hour.\r\n" );
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document.write( "To solve it, multiply all the terms by 150. you will get then\r\n" );
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document.write( " 6d - 5d =  \r\n" );
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document.write( " d = 75.\r\n" );
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document.write( "ANSWER. The distance from the house to the office is 75 miles.\r\n" );
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document.write( "CHECK. Time to the office  = 3 hours.\r\n" );
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document.write( " Time returning back is  = 2.5 hours.\r\n" );
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document.write( " The difference is 3 - 2.5 = 0.5 of an hour, correct.\r\n" );
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document.write( "Solved.\r
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