document.write( "Question 1203645: How to solve for the inverse of: 1/ (2x) +3 ( three being beside the fraction not in the denominator
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Algebra.Com's Answer #839375 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "if you have \r
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\n" ); document.write( "\n" ); document.write( "\"y=1%2F%282x%29+%2B3\"....swap variables\r
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\n" ); document.write( "\n" ); document.write( "\"x=1%2F+2y+%2B3\"....solve for\"++y\"\r
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\n" ); document.write( "\n" ); document.write( "\"x-3=1%2F+2y+\"\r
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\n" ); document.write( "\n" ); document.write( "\"2y+%28x-3%29=1+\"\r
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\n" ); document.write( "\n" ); document.write( "\"2y+=1%2F+%28x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=1%2F2%28x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "so, inverse is\r
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\n" ); document.write( "\n" ); document.write( "\"y\"'=\"+1%2F2%28x-3%29\"\r
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