document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1203629>Question 1203629</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A student received scores of 84, 73, and 71 on their midterm algebra exams. If the final exam counts twice as much as a midterm, what score must the student make on their final exam to get an average score of 80? (Assume that the maximum possible score on each test is 100.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #839330 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=839330\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i feel like something is missing in this problem.<BR>\n" );
document.write( "what i think is missing is how much a midterm counts.<BR>\n" );
document.write( "the way the problem is posed, the midterm doesn't count any more than a regular test.<BR>\n" );
document.write( "if that's true, then the final counts twice as much as any test, not just the miderm, since the midterm doesn't count any more than a regular test.<BR>\n" );
document.write( "with that in mind, i calculated as follows.<BR>\n" );
document.write( "you have 3 regulars test that counts for 1 each.<BR>\n" );
document.write( "the final counts as twice the midterm, which effectively means that it counts twice as much as any test, not just the midterm.\<BR>\n" );
document.write( "if you let x equal the score of the midterm, then you get:<BR>\n" );
document.write( "the sum of the scores on the 3 other test plus twice the score on the final should be equal to the sum of all the scores.<BR>\n" );
document.write( "that gets you:<BR>\n" );
document.write( "84 + 73 + 71 + 2x = 5 * 80 = 400<BR>\n" );
document.write( "simplify to get:<BR>\n" );
document.write( "228 + 2x = 400<BR>\n" );
document.write( "subtract 228 from both sides of that equation to get:<BR>\n" );
document.write( "2x = 172<BR>\n" );
document.write( "solve for x to get x = 172/2 = 86\r<BR>\n" );
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document.write( "you require an 86 on the final to get an overall average of 80, assuming the final score counts twice as much as the scores on the other 3 tests.<BR>\n" );
document.write( "228 + 2 * 86 = 400 / 5 = an overall average of 80, confirming the final test value is good.\r<BR>\n" );
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document.write( "the total number of scores to consider are 3 from the other tests plus 2 from the final.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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