document.write( "Question 1203624: Tina was three times younger than Helen in 2006. In 2012 Helen will be 42. How old will Tina be in 2012? \n" ); document.write( "
Algebra.Com's Answer #839328 by ankor@dixie-net.com(22740)\"\" \"About 
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Tina was three times younger than Helen in 2006.
\n" ); document.write( " 3t = h
\n" ); document.write( "In 2012 Helen will be 42.
\n" ); document.write( "h + 6 = 42
\n" ); document.write( "How old will Tina be in 2012?
\n" ); document.write( ":
\n" ); document.write( "Six years later
\n" ); document.write( "3t+6 = h+6
\n" ); document.write( " h+6=42 therefore
\n" ); document.write( "3t + 6 = 42
\n" ); document.write( "3t = 42 - 6
\n" ); document.write( "3t = 36
\n" ); document.write( "t = 36/12
\n" ); document.write( "t = 12 in 2006
\n" ); document.write( "Therefore 6 years in 2012, Tina will be 18
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