document.write( "Question 1203624: Tina was three times younger than Helen in 2006. In 2012 Helen will be 42. How old will Tina be in 2012? \n" ); document.write( "
Algebra.Com's Answer #839328 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Tina was three times younger than Helen in 2006. \n" ); document.write( " 3t = h \n" ); document.write( "In 2012 Helen will be 42. \n" ); document.write( "h + 6 = 42 \n" ); document.write( "How old will Tina be in 2012? \n" ); document.write( ": \n" ); document.write( "Six years later \n" ); document.write( "3t+6 = h+6 \n" ); document.write( " h+6=42 therefore \n" ); document.write( "3t + 6 = 42 \n" ); document.write( "3t = 42 - 6 \n" ); document.write( "3t = 36 \n" ); document.write( "t = 36/12 \n" ); document.write( "t = 12 in 2006 \n" ); document.write( "Therefore 6 years in 2012, Tina will be 18 \n" ); document.write( " |