document.write( "Question 1203599: The formula for an investment worth with interest compounded annually is A=P(1+i)^n, where P represents the initial investment, i is the interest rate, and A is the worth of the investment after n years.\r
\n" ); document.write( "\n" ); document.write( "a) Rearrange the formula for P. What was the initial investment of an investment worth $1000 that compounded 10% interest for 10 years?
\n" ); document.write( "b) Rearrange the formula for i. What is the interest rate of an investment whose worth went from $1000 to $1200 in 2 years?
\n" ); document.write( "c) Explain a method with which you could estimate how many years it would take for an investment to reach a certain worth at a certain interest rate.
\n" ); document.write( "d) Estimate how many years would it take an investment of $2100 at 20% interest to reach a worth of $5225?\r
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Algebra.Com's Answer #839293 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( " The formula for an investment worth with interest compounded annually is \r
\n" ); document.write( "\n" ); document.write( "\"A=P%281%2Bi%29%5En\"\r
\n" ); document.write( "\n" ); document.write( "where\"+P\" represents the initial investment,\"+i+\"is the interest rate, and \"A+\"is the worth of the investment after \"n\" years.\r
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\n" ); document.write( "\n" ); document.write( "a) Rearrange the formula for\"+P\". What was the initial investment of an investment worth $\"1000\" that compounded \"10\"% interest for\"+10\" years?\r
\n" ); document.write( "\n" ); document.write( "\"A=P%281%2Bi%29%5En\"\r
\n" ); document.write( "\n" ); document.write( "\"P=A%2F%281%2Bi%29%5En\"\r
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\n" ); document.write( "\n" ); document.write( "if\r
\n" ); document.write( "\n" ); document.write( "\"A=1000\"
\n" ); document.write( " \"i=10\"%=\"0.10\"
\n" ); document.write( "\"n=10\"\r
\n" ); document.write( "\n" ); document.write( "\"P=1000%2F%281%2B0.10%29%5E10\"\r
\n" ); document.write( "\n" ); document.write( "\"P=385.54\"\r
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\n" ); document.write( "\n" ); document.write( "b) Rearrange the formula for\"+i\". What is the interest rate of an investment whose worth went from $\"1000\" to $\"1200\" in \"2+\"years?\r
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\n" ); document.write( "\n" ); document.write( "\"A=P%281%2Bi%29%5En\"\r
\n" ); document.write( "\n" ); document.write( "\"A%2FP=%281%2Bi%29%5En\"\r
\n" ); document.write( "\n" ); document.write( "\"root%28n%2CA%2FP%29=1%2Bi\"\r
\n" ); document.write( "\n" ); document.write( "\"+i=root%28n%2CA%2FP%29-1\"\r
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\n" ); document.write( "\n" ); document.write( "if\r
\n" ); document.write( "\n" ); document.write( "\"P=1000+\"
\n" ); document.write( "\"A=1200\"
\n" ); document.write( "\"n+=2\" years\r
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\n" ); document.write( "\n" ); document.write( "\"+i=root%282%2C1200%2F1000%29-1\"\r
\n" ); document.write( "\n" ); document.write( "\"+i=root%282%2C12%2F10%29-1\"\r
\n" ); document.write( "\n" ); document.write( "\"+i=root%282%2C6%2F5%29-1\"\r
\n" ); document.write( "\n" ); document.write( "\"+i=1.096-1\"\r
\n" ); document.write( "\n" ); document.write( "\"+i=0.095445\" or \"i=9.5445\"%\r
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\n" ); document.write( "\n" ); document.write( "c) Explain a method with which you could estimate how many years it would take for an investment to reach a certain worth at a certain interest rate.\r
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\n" ); document.write( "\n" ); document.write( "The Rule of \"72\" is a calculation that estimates the number of years it takes to double your money at a specified rate of return. \r
\n" ); document.write( "\n" ); document.write( "for example\r
\n" ); document.write( "\n" ); document.write( " $\"100\" at \"10\"% will double to $\"200+\"in: \"72%2F10=7.2\" years\r
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\n" ); document.write( "\n" ); document.write( "d) Estimate how many years would it take an investment of $\"2100\" at\"+20\"% interest to reach a worth of $\"5225\"?\r
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\n" ); document.write( "\n" ); document.write( "Note: We don't have to \"estimate\" but will solve it exactly!!!\r
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\n" ); document.write( "\n" ); document.write( "to reach a worth of $\"5225+\"will be\r
\n" ); document.write( "\n" ); document.write( "\"5225=2100%281%2B0.20%29%5En\"\r
\n" ); document.write( "\n" ); document.write( "\"n\"\"4.9995+\"\r
\n" ); document.write( "\n" ); document.write( "\"n\"\"5+\"years\r
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