document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1203594>Question 1203594</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Juan cut out a polygon with scissors and card board.  All the angles in the polygon were acute.  What type of polygon could he have drawn?\r<BR>\n" );
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document.write( "A. pentagon<BR>\n" );
document.write( "B. octagon<BR>\n" );
document.write( "C. triangle (correct answer)<BR>\n" );
document.write( "D. hexagon\r<BR>\n" );
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document.write( "I need to know how to determine the correct answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #839265 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=839265\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "\"acute\" means the measure of an angle is less than 90 degrees.<br><BR>\n" );
document.write( "For a triangle, the sum of the angle measures is 180 degrees, so the average of the angle measures is 180/3 = 60 degrees.  Since that is less than 90 degrees, the polygon he drew could have been a triangle.<br><BR>\n" );
document.write( "For a quadrilateral, the sum of the angle measures is 360 degrees, so the average of the angle measures is 360/4 = 90 degrees.  Since that is not less than 90 degrees, the polygon he drew could not have been a quadrilateral.<br><BR>\n" );
document.write( "For polygons with more than 4 sides, the average of the angle measures is always greater then 90 degrees, so it is not possible that the polygon he drew has more then 4 sides.<br><BR>\n" );
document.write( "ANSWER: triangle<br><BR>\n" );
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