document.write( "Question 1203588: what is the coefficient of the 5th term of the expansion of (2x^2 + 3y^3)^10 how about the sum of exponents of the terms in expansion\r
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Algebra.Com's Answer #839264 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "To find the coefficient of the \"5\"th term in the expansion of \"%282x%5E2%2B+3y%5E3%29%5E10\", we need to use the binomial theorem. \r
\n" ); document.write( "\n" ); document.write( "The general term in the expansion of \"%282x%5E2%2B+3y%5E3%29%5E10\" is given by:\r
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\n" ); document.write( "\n" ); document.write( "\"T%28r%2B1%29+=+C%2810%2C+r%29+%2A+%282x%5E2%29%5E%2810-r%29+%2A+%283y%5E3%29%5Er\"\r
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\n" ); document.write( "\n" ); document.write( "where \"C%2810%2C+r%29\" is the binomial coefficient of \"10\" and \"r\", given by:\r
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\n" ); document.write( "\n" ); document.write( "\"C%2810%2C+r%29+=+10%21+%2F+%28r%21+%2A+%2810+-+r%29%21%29\"\r
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\n" ); document.write( "\n" ); document.write( "To find the \"5\"th term, we need to substitute \"r+=+4\", since the first term has \"r+=+0\". Therefore, the \"5\"th term is:\r
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\n" ); document.write( "\n" ); document.write( "\"T%285%29+=+C%2810%2C+4%29+%2A+%282x%5E2%29%5E%2810-4%29+%2A+%283y%5E3%29%5E4\"\r
\n" ); document.write( "\n" ); document.write( "= \"C%2810%2C+4%29+%2A+%282x%5E2%29%5E6+%2A+%283y%5E3%29%5E4\"\r
\n" ); document.write( "\n" ); document.write( "= \"210+%2A+64x%5E12+%2A+81y%5E12\"\r
\n" ); document.write( "\n" ); document.write( "= \"1088640x%5E12%2Ay%5E12\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the coefficient of the \"5\"th term in the expansion of \"%282x%5E2+%2B+3y%5E3%29%5E10\" is \"1088640\".\r
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