document.write( "Question 1203585: The time required to complete a college achievement test was foundto be normally\r
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document.write( "distributed, with a mean of 110 minutes and standard deviation of20 minutes.\r
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document.write( "(a) What proportion of the students will ?nish within 2 hours (120minutes)?\r
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document.write( "(b) What proportion of the students will ?nish at exactly 2hours?\r
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document.write( "(c) When should the test be terminated to allow just enough timefor 90% of the\r
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document.write( "students to complete the test \n" );
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Algebra.Com's Answer #839259 by Theo(13342)![]() ![]() You can put this solution on YOUR website! mean is 110 minutes. \n" ); document.write( "standard deviation is 20 minutes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "use the z-score formula. \n" ); document.write( "it is z = (x - m) / s \n" ); document.write( "z is the z-score \n" ); document.write( "m is the population mean \n" ); document.write( "s is the standard deviation \n" ); document.write( "x is the student score\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The time required to complete a college achievement test was found to be normally distributed, with a mean of 110 minutes and standard deviation of20 minutes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(a) What proportion of the students will finish within 2 hours (120 minutes)?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = (120 - 110) / 20 = .5 \n" ); document.write( "area to the left of a z-score of .5 = .6915. \n" ); document.write( "this means that 69.15% of the participants will complete the test in 120 minutes or less.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(b) What proportion of the students will finish at exactly 2 hours?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the theory says that, because this is a continuous curve, the probability of getting exactly 120 minutes is 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's refference that addresses that issue. \n" ); document.write( "https://sphweb.bumc.bu.edu/otlt/mph-modules/bs/bs704_probability/bs704_probability8.html#:~:text=Note%20that%20with%20the%20normal,is%20%3C%2029%20is%2050%25.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the particular statement in that reference is: \n" ); document.write( "Note that with the normal distribution the probability of having any exact value is 0 because there is no area at an exact BMI value, so in this case, the probability that his BMI = 29 is 0, but the probability that his BMI is <29 or the probability that his BMI is < 29 is 50%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(c) When should the test be terminated to allow just enough time for 90% of the \n" ); document.write( "students to complete the test.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z-score that has 90% of the area under the normal distribution curve to the left of it is equal to 1.2816. \n" ); document.write( "z-score formula becomes: \n" ); document.write( "1.2816 = (x - 110) / 20 \n" ); document.write( "solve for x to get x = 20 * 1.2816 + 110 = 135.632. \n" ); document.write( "that's the number of minutes that the test would be terminated so that 90% of the participants will have been able to complete the test. \n" ); document.write( "any rounding should be rounding up to ensure at least 90%.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |