document.write( "Question 1203587: A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air resistance, its height in feet t seconds after launch is given by s=-16t^2+v0t . Find the time(s) that the projectile will (a) reach a height of 288 ft and (b) return to the ground when v0=144 feet per second.
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document.write( "(b) The projectile returns to the ground after
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document.write( "enter your response here second(s). \n" );
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Algebra.Com's Answer #839257 by math_tutor2020(3816)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Part (a)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "s = -16t^2 + v0*t \n" ); document.write( "s = -16t^2 + 144t \n" ); document.write( "288 = -16t^2 + 144t \n" ); document.write( "0 = -16t^2 + 144t - 288 \n" ); document.write( "-16t^2 + 144t - 288 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We can then factor \n" ); document.write( "-16t^2 + 144t - 288 = 0 \n" ); document.write( "-16(t^2 - 9t + 18) = 0 \n" ); document.write( "-16(t - 3)(t - 6) = 0 \n" ); document.write( "t-3 = 0 or t-6 = 0 \n" ); document.write( "t = 3 or t = 6\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Or we can use the quadratic formula \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Either way, the two answers for part (a) are t = 3 and t = 6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The projectile reaches 288 ft at t = 3 seconds when going upward. \n" ); document.write( "Upon its downward trajectory, it gets back to a height 288 ft at t = 6 seconds.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The projectile is above 288 ft for the interval 3 < t < 6. Otherwise, the projectile is at 288 ft or lower.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (b)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "s = -16t^2 + 144t \n" ); document.write( "-16t^2 + 144t = s \n" ); document.write( "-16t^2 + 144t = 0 \n" ); document.write( "-16t(t - 9) = 0 \n" ); document.write( "-16t = 0 or t-9 = 0 \n" ); document.write( "t = 0/(-16) or t = 9 \n" ); document.write( "t = 0 or t = 9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The projectile starts on the ground, so it makes sense that t = 0 is one solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The other solution is t = 9 which is when the rocket returns to the ground again. \n" ); document.write( "The flight time is 9 seconds. \n" ); document.write( " \n" ); document.write( " |