document.write( "Question 1203553: Theorem 1.4.3 is
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document.write( "P(AuB)=P(AnB')+P(B)
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document.write( "= [P(A) - P(A n B)] + P(B)
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document.write( "= P(A) + P(B) - P(A n B)\r
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document.write( "Theorem 1.4.4 is
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document.write( "P(A u B u C) = P(A) + P(B) + P(C)
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document.write( "- P(A n B) - P(A n C) - P(B n C)
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document.write( "+ P(A n B n C)\r
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document.write( "Prove Theorem 1.4.4. Hint: Write A u B u C = (A u B) u Cand apply Theorem 1.4.3. \n" );
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Algebra.Com's Answer #839219 by ikleyn(52800)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "In order to understand the formula of inclusion-exclusion principle,\r\n" ); document.write( "it is very useful to keep in mind this simple reasoning.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "When we calculate the sum \r\n" ); document.write( "\r\n" ); document.write( " P(A) + P(B) + P(C) for P(A U B U C), (1)\r\n" ); document.write( "\r\n" ); document.write( "it seems very natural and does not arouse suspicion - so, it looks as a good first approximation.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "But thinking longer, you understand that every part P(A n B), P(A n C) and P(B n C)\r\n" ); document.write( "you count twice in this sum P(A) + P(B) + P(C).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Therefore, next step is to subract P(A n B) + P(A n C) + P(B n C) from the sum P(A) + P(B) + P(C).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "So, you get then P(A) + P(B) + P(C) - P(A n B) - P(A n C) - P(B n C). (2)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "It is good as the next, second approximation.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "But thinking further, you understand that in expression P(A) + P(B) + P(C) - P(A n B) - P(A n C) - P(B n C)\r\n" ); document.write( "\r\n" ); document.write( "the part P(A n B n C) is added three times in the first three addends and subtracted three times\r\n" ); document.write( "\r\n" ); document.write( "in the next three terms. So, now this part P(A n B n C) simply ABSENTS in the second approximation (2).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "THEREFORE, you MUST add P(A n B n C) to (2), and after doing it, you get\r \n" ); document.write( "\n" ); document.write( "As soon as you got this reasoning and placed it in your mind, \n" ); document.write( "you do understand the Inclusion-Exclusion principle in whole.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |