document.write( "Question 1203530: three contractors a b c have constructed buildings in a society in which 2%3%and 4% of the buildings constructed respectively by a b c have water leakage in the building if they have constructed 50%30%20% of the buildings in a society respectively a building is selected and found that it has water leakage interpret which contractor would you guess did construct the building\r
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Algebra.Com's Answer #839183 by ikleyn(52879)\"\" \"About 
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\n" ); document.write( "three contractors a b c have constructed buildings in a society in which 2%3%and 4% of the buildings
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\n" ); document.write( "\n" ); document.write( "        Your writing/printing is terrible.\r
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document.write( "This problem is about conditional probability.\r\n" );
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document.write( "They want you find three conditional probabilities \r\n" );
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document.write( "    P(leakage is from A given that there is a leakage)\r\n" );
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document.write( "    P(leakage is from B given that there is a leakage)\r\n" );
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document.write( "    P(leakage is from C given that there is a leakage)\r\n" );
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document.write( "then compare these values and select the maximum of the three.\r\n" );
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document.write( "    P(leakage is from A given that there is a leakage) = \"%280.02%2A0.5%29%2F%280.02%2A0.5+%2B+0.03%2A0.3+%2B+0.04%2A0.2%29\" = 0.3704,\r\n" );
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document.write( "    P(leakage is from B given that there is a leakage) = \"%280.03%2A0.3%29%2F%280.02%2A0.5+%2B+0.03%2A0.3+%2B+0.04%2A0.2%29\" = 0.3333,\r\n" );
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document.write( "    P(leakage is from C given that there is a leakage) = \"%280.04%2A0.2%29%2F%280.02%2A0.5+%2B+0.03%2A0.3+%2B+0.04%2A0.2%29\" = 0.2963.\r\n" );
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document.write( "Of these three probabilities, the greatest is from A; so, we can suspect that the leakage is from A.\r\n" );
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document.write( "The structure of these formulas is the same: the denominator is the probability \r\n" );
document.write( "having a leakage (from any of the three buildings);\r\n" );
document.write( "the numerators are individual probabilities having leakage from A, B, or C, respectively.\r\n" );
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document.write( "Since the denominator is the same in all three formulas, we could cut down our calculations for this problem\r\n" );
document.write( "by computing the numerators only.\r\n" );
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document.write( "But I did the full job in order for the interior logic be CLEAR for the reader.\r\n" );
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