document.write( "Question 1203535: You need to strengthen a 22% alcohol solution with a pure alcohol solution to obtain a 70% solution. How much pure alcohol should you add to 100 milliliters of the 22% solution? \n" ); document.write( "
Algebra.Com's Answer #839177 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
The problem can be done all in variables, but seems easier to handle using a table of data.
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document.write( "MATERIAL CONC.%         VOLUME         AMOUNT PURE\r\n" );
document.write( "         22              100             22*100\r\n" );
document.write( "        100               v              100v\r\n" );
document.write( "         70              v+100           70(v+100)\r\n" );
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\n" ); document.write( "\n" ); document.write( "Question asks for how much of the pure 100% alcohol to add, v.\r
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\n" ); document.write( "\n" ); document.write( "Accounting for the amount of alcohol for the separate parts,
\n" ); document.write( "\"100v%2B22%2A100=70%28v%2B100%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"100v%2B22%2A100=70v%2B70%2A100\"\r
\n" ); document.write( "\n" ); document.write( "\"%28100-70%29v=70%2A100-22%2A100\"\r
\n" ); document.write( "\n" ); document.write( "\"v=100%28%2870-22%29%2F%28100-70%29%29\"-------simplify and compute.\r
\n" ); document.write( "\n" ); document.write( "\"v=100%2848%2F30%29\"\r
\n" ); document.write( "\n" ); document.write( "\"v=100%281.6%29\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28v=160%29\"---------ml. of the pure 100% alcohol to use
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