document.write( "Question 1203527: A truck can be rented from Company A for ​$80 a day plus ​$0.40 per mile. Company B charges ​$50 a day plus ​$0.90 per mile to rent the same truck. Find the number of miles in a day at which the rental costs for Company A and Company B are the same.
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Algebra.Com's Answer #839169 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "x = number of miles
\n" ); document.write( "y = total cost in dollars\r
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\n" ); document.write( "\n" ); document.write( "Company A: y = 0.40x+80
\n" ); document.write( "Company B: y = 0.90x+50\r
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\n" ); document.write( "\n" ); document.write( "Equate the right hand sides to solve for x.
\n" ); document.write( "0.90x+50 = 0.40x+80
\n" ); document.write( "0.90x-0.40x = 80-50
\n" ); document.write( "0.50x = 30
\n" ); document.write( "x = 30/0.50
\n" ); document.write( "x = 60\r
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\n" ); document.write( "\n" ); document.write( "Driving 60 miles means the two costs are the same. Each cost is $104 because of the scratch work below.
\n" ); document.write( "y = 0.40x+80
\n" ); document.write( "y = 0.40*60+80
\n" ); document.write( "y = 24+80
\n" ); document.write( "y = 104
\n" ); document.write( "and also
\n" ); document.write( "y = 0.90x+50
\n" ); document.write( "y = 0.90*60+50
\n" ); document.write( "y = 54+50
\n" ); document.write( "y = 104
\n" ); document.write( "Both equations have x = 60 lead to y = 104\r
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\n" ); document.write( "\n" ); document.write( "Answer: 60 miles
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