document.write( "Question 1203438: 3x+6y-z=6
\n" ); document.write( "3x-3y+5z=-6
\n" ); document.write( "9x+9y-2z=11
\n" ); document.write( "

Algebra.Com's Answer #839013 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "There are an endless number of different ways to solve this system of equations; the other tutor has shown one.

\n" ); document.write( "Like the other tutor, I changed the three equations into equivalent forms to get \"9x\" as a term in all three equations. Then from there I went a different direction the they did.

\n" ); document.write( "\"9x%2B18y-3z=18\" [1]
\n" ); document.write( "\"9x-9y%2B15z=-18\" [2]
\n" ); document.write( "\"9x%2B9y-2z=11\" [3]

\n" ); document.write( "Do [1]-[2] to eliminate x to get one equation in y and z; do [1]-[3] to get another.

\n" ); document.write( "\"27y-18z=36\" --> \"9y-6z=12\" [4]
\n" ); document.write( "\"9y-z=7\" [5]

\n" ); document.write( "Do [4]-[5] to eliminate y and solve for z

\n" ); document.write( "\"-5z=5\"
\n" ); document.write( "\"z=-1\"

\n" ); document.write( "Substitute z=-1 in [5] and solve for y

\n" ); document.write( "\"9y%2B1=7\"
\n" ); document.write( "\"9y=6\"
\n" ); document.write( "\"y=6%2F9=2%2F3\"

\n" ); document.write( "Substitute z=-1 and y=2/3 in [1] to solve for x

\n" ); document.write( "\"9x%2B12%2B3=18\"
\n" ); document.write( "\"9x%2B15=18\"
\n" ); document.write( "\"9x=3\"
\n" ); document.write( "\"x=3%2F9=1%2F3\"

\n" ); document.write( "ANSWER: (x,y,z) = (1/3,2/3,-1)

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