document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1203425>Question 1203425</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a metal weighing 6 mg and containing 4% copper is melted and mixed with 2 mg of a different alloy which contains 80% copper.What percent of the resulting alloy is copper?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #838983 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=838983\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "A fast and easy informal solution, if your mental arithmetic is good....<br><BR>\n" );
document.write( "The fraction of the mixture that contains the higher percentage of copper is 2/(6+2) = 2/8 = 1/4.<br><BR>\n" );
document.write( "That means the percentage of copper in the mixture is 1/4 of the way from 4% to 80%.<br><BR>\n" );
document.write( "From 4% to 80% is a difference of 76%; 1/4 of that is 19%.<br><BR>\n" );
document.write( "The percentage of copper in the mixture is 4%+19% = 23%.<br><BR>\n" );
document.write( "ANSWER: 23%<br><BR>\n" );
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