document.write( "Question 1203426: 14 oz.of mixed nuts containing 15% peanuts were mixed with 16 oz.of another kind of mixed nuts that contain 60% peanuts.Peanuts are what percent of the new mixture?
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Algebra.Com's Answer #838981 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Here is an alternative to the standard formal algebraic solution for solving 2-part mixture problems like the one shown by the other tutor.

\n" ); document.write( "For this problem, it is not an efficient method; but for many similar problems it is faster and easier than formal algebra.

\n" ); document.write( "The fraction of the mixture that is 60% peanuts is 16/(14+16) = 16/30 = 8/15.

\n" ); document.write( "That means the percentage of peanuts in the mixture is 8/15 of the way from 15% to 60%.

\n" ); document.write( "From 15% to 60% is a difference of 45%; 8/15 of 45% is 24%. The percentage of peanuts in the mixture is 15%+24% = 39%.

\n" ); document.write( "ANSWER: 39%

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