document.write( "Question 1203426: 14 oz.of mixed nuts containing 15% peanuts were mixed with 16 oz.of another kind of mixed nuts that contain 60% peanuts.Peanuts are what percent of the new mixture?
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Algebra.Com's Answer #838976 by Theo(13342)\"\" \"About 
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14 ounces of mixed nuts type 1 + 16 ounces of mixed nuts type 2 = 30 ounces of mixed nuts type 3, where type 3 = type 1 + type 2 combined.\r
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\n" ); document.write( "\n" ); document.write( ".15 * 14 + .6 * 16 = 2.1 + 9.6 = 11.7 ounces of peanuts in 30 ounces of type 3 mixture.\r
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\n" ); document.write( "\n" ); document.write( "11.7 / 30 = .39 * 100 = 39% of peanuts in 30 ounces of mixed nuts type 3.\r
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\n" ); document.write( "\n" ); document.write( "since type 3 is the new mixture, your solution is 39% peanuts in the new mixture.\r
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