document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1203419>Question 1203419</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 12 ml of a 65% alcohol solution was mixed with 8 ml of an 80% alcohol solution. What is the concentration of the mixture?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #838972 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=838972\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is an informal method for solving this kind of 2-part mixture problem that is completely different from the standard formal algebraic methods shown by the other tutors....<br><BR>\n" );
document.write( "The fraction of the mixture that is 80% alcohol is 8/(12+8) = 8/20 = 2/5.<br><BR>\n" );
document.write( "That means the percentage of the mixture is 2/5 of the way from 65% to 80%.<br><BR>\n" );
document.write( "From 65% to 80% is a difference of 15%; 2/5 of that is 6%.  The percentage of the mixture is 65+6 = 71%.<br><BR>\n" );
document.write( "ANSWER: 71%<br><BR>\n" );
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