document.write( "Question 1203395: ax+ b = c solve for x
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Algebra.Com's Answer #838921 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "ax means \"a times x\"
\n" ); document.write( "Adjacent letters together like this usually indicates multiplication.\r
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\n" ); document.write( "\n" ); document.write( "We start with some unknown number x.
\n" ); document.write( "We then multiply it with 'a' to get ax
\n" ); document.write( "Then add on b to get ax+b\r
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\n" ); document.write( "\n" ); document.write( "The order of this is important because we follow those operations in reverse to undo them. This will isolate x.\r
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\n" ); document.write( "\n" ); document.write( "How do we undo the \"add b\" part? By subtracting b from both sides.
\n" ); document.write( "Undoing the \"multiply by a\" part means we divide both sides by 'a'.
\n" ); document.write( "These are called inverse operations.\r
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\n" ); document.write( "\n" ); document.write( "Here are the steps to isolate x.
\n" ); document.write( "\"ax+%2B+b+=+c\"\r
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\n" ); document.write( "\n" ); document.write( "\"ax+%2B+b-b+=+c-b\" Subtracted b from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"ax+=+c-b\"\r
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\n" ); document.write( "\n" ); document.write( "\"ax%2Fa+=+%28c-b%29%2Fa\" Divide both sides by 'a' (we must require that \"a+%3C%3E+0\" to avoid division by zero errors)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28c-b%29%2Fa\" And we're done. The x is all by itself now.\r
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\n" ); document.write( "\n" ); document.write( "Here's a slightly more concrete example\r
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\n" ); document.write( "\n" ); document.write( "Say we had 2x+5 = 37 as our equation.
\n" ); document.write( "I replaced 'a' with 2, replaced b with 5, and c with 37.
\n" ); document.write( "Pick any three numbers you want. As long as 'a' is nonzero. \r
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\n" ); document.write( "\n" ); document.write( "We'll subtract 5 from both sides to undo the \"plus 5\".
\n" ); document.write( "Then divide both sides by 2 to undo the \"multiply by 2\".
\n" ); document.write( "Follow PEMDAS in reverse to isolate the variable. \r
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\n" ); document.write( "\n" ); document.write( "\"2x+%2B+5+=+37\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x+%2B+5-5+=+37-5\" Subtract 5 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"2x+=+37-5\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2F2+=+%2837-5%29%2F2\" Divided both sides by 2\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2837-5%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "I'll leave the right hand side unevaluated so you can see how it fits the format \"%28c-b%29%2Fa\"
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