document.write( "Question 1203395: ax+ b = c solve for x
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Algebra.Com's Answer #838921 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "ax means \"a times x\" \n" ); document.write( "Adjacent letters together like this usually indicates multiplication.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We start with some unknown number x. \n" ); document.write( "We then multiply it with 'a' to get ax \n" ); document.write( "Then add on b to get ax+b\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The order of this is important because we follow those operations in reverse to undo them. This will isolate x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "How do we undo the \"add b\" part? By subtracting b from both sides. \n" ); document.write( "Undoing the \"multiply by a\" part means we divide both sides by 'a'. \n" ); document.write( "These are called inverse operations.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here are the steps to isolate x. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----------------------------------\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here's a slightly more concrete example\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Say we had 2x+5 = 37 as our equation. \n" ); document.write( "I replaced 'a' with 2, replaced b with 5, and c with 37. \n" ); document.write( "Pick any three numbers you want. As long as 'a' is nonzero. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We'll subtract 5 from both sides to undo the \"plus 5\". \n" ); document.write( "Then divide both sides by 2 to undo the \"multiply by 2\". \n" ); document.write( "Follow PEMDAS in reverse to isolate the variable. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll leave the right hand side unevaluated so you can see how it fits the format \n" ); document.write( " \n" ); document.write( " |