document.write( "Question 115302: If log3(x+1)-log3(x-1)=2, then x=A/8 where A= \n" ); document.write( "
Algebra.Com's Answer #83892 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If log3(x+1)-log3(x-1)=2, then x=A/8 where A= \n" ); document.write( "----------------- \n" ); document.write( "The base is \"3, so: \n" ); document.write( "log[(x+1)/(x-1)] = 2 \n" ); document.write( "[(x+1)/(x-1)] = 3^2 \n" ); document.write( "x+1 = 9x-9 \n" ); document.write( "8x = 10 \n" ); document.write( "x = 5/4 \n" ); document.write( "---------- \n" ); document.write( "If x = A/8 \n" ); document.write( "then (5/4) = A/8 \n" ); document.write( "A = 10\r \n" ); document.write( "\n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |