document.write( "Question 115302: If log3(x+1)-log3(x-1)=2, then x=A/8 where A= \n" ); document.write( "
Algebra.Com's Answer #83892 by stanbon(75887)\"\" \"About 
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If log3(x+1)-log3(x-1)=2, then x=A/8 where A=
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\n" ); document.write( "The base is \"3, so:
\n" ); document.write( "log[(x+1)/(x-1)] = 2
\n" ); document.write( "[(x+1)/(x-1)] = 3^2
\n" ); document.write( "x+1 = 9x-9
\n" ); document.write( "8x = 10
\n" ); document.write( "x = 5/4
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\n" ); document.write( "If x = A/8
\n" ); document.write( "then (5/4) = A/8
\n" ); document.write( "A = 10\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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